আপনি মেটা অক্ষর “\\B” ব্যবহার করে অ-শব্দ সীমানা মেলাতে পারেন।
উদাহরণ 1
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String args[]) {
//Reading String from user
System.out.println("Enter a String");
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
String regex = "\\B";
//Compiling the regular expression
Pattern pattern = Pattern.compile(regex);
//Retrieving the matcher object
Matcher matcher = pattern.matcher(input);
int count = 0;
while(matcher.find()) {
count++;
}
System.out.println("Number of non-word boundaries: "+count);
}
} আউটপুট
Enter a String this is a sample text Number of non-word boundaries: 12
উদাহরণ 2
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main( String args[] ) {
String regex = "\\Bin";
Scanner sc = new Scanner(System.in);
System.out.println("Enter a string: ");
String input = sc.nextLine();
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(input);
int count = 0;
while(m.find()) {
count++;
}
System.out.println("no of non-word boundaries: "+count);
}
} আউটপুট
Enter a string: this is a sample text in win tin pin sin no of non-word boundaries: 4
